Here we learn to multiply a 2-digit number by a 1-digit number. We learn to multiply a two-digit number by a single-digit number in two different ways.

Examples of multiplying a 2-digit number by a 1-digit number without regrouping:

We’re going to give a brief overview of multiplying a 2-digit number by a 1-digit number without regrouping:

1. Multiply 34 and 2


Solution:

Step I: Arrange the numbers vertically.

Step II: First multiply the number in the units place by 2.

2 × 4 = 8 ones

Step III: Now multiply the number in the tens place by 2.

2 × 3 = 6 tens

Multiply a 2-digit number by a 1-digit number

So 34 × 2 = 68

2. Multiply 20 by 3 using the expanded form

Solution:

20 → 2 tens + 0 ones

× 3 × 3

6 tens + 0 ones

= 60 + 0

= 60

Hence 20 × 3 = 60

3. Multiply 50 by 1 in the short form

Solution:

50 → 50

× 1× 1

0 50

(i) The first digit of the own digit is multiplied by 1, ie 0 × 1 = 0

(ii) Then the digit in the tens is multiplied by 1, ie 5 tens × 1 = 5 tens

Hence 50 × 1 = 50

4. Multiply 25 by 3

Step I: Arrange the numbers vertically.

Step II: First multiply the number in the units place by 3.

3 × 5 = 15 = 1 ten + 5 ones one

Write 5 in the units column and transfer 1 to the tens column

Step III: Now multiply the number in the tens place by 3.

3 × 2 = 6 tens

Well, 6 + 1 (carried over) = 7 tens

Multiply a 2-digit number by a 1-digit number with regrouping

So 25 × 3 = 75

5. Multiply 46 by 4

Step I: Arrange the numbers vertically.

Step II: Multiply the number in the ones place by 4.

6 × 4 = 24 = 2 tens + 4 ones

Write 4 in the units column and transfer 2 to the tens column

Step III: Now multiply the number in the tens place by 4.

4 × 4 = 16 tens

Well, 16 + 2 (transferred) = 18 tens = 1 hundred + 8 tens

Write 8 for the tens and 1 for the hundreds.

Multiply the 2-digit number by the 1-digit number with regrouping

So 46 × 4 = 184

6th Multiply 20 by 3 using the expanded form

Solution:

20 → 2 tens + 0 ones

× 3 × 3

6 tens + 0 ones

= 60 + 0

= 60

Hence 20 × 3 = 60

7thMultiply 26 by 7 using the expanded form

Solution:

26 → 20 + 6 → 2 tens + 6 ones

× 7th × 7 × 7

(2 × 7) tens + (6 × 7) ones

2 tens + 6 ones

× 7 ones

14 tens + 42 ones

= 14 tens + (40 + 2) ones

= 14 tens + 4 tens + 2 ones

= 18 tens + 2 ones

= 180 + 2

= 182

Hence 26 × 7 = 182

8th.Multiply 48 by 6 using the short form

Solution:

48

× 6th

24 48

= 28 tens 8 ones

= 288

Hence 48 × 6 = 288

(i) 48 × 6 is written in the column of.

(ii) 8 ones are multiplied by 6, i.e. 6 × 8 = 48 ones = 4 tens + 8 ones

8 is written in your own column and 4 tens is won.

(iii) The 4 won is transferred to the 10 column.

(iv) Now 4 tens are multiplied by 6, ie 4 tens × 6 = 24 tens

(v) 4 tens are added to 24 tens, ie 4 tens + 24 tens = 28 tens

9.Find the product of 58 × 5.

Solution:

58

× 5

25 ← 40

= 25 + 4 ← 0

= 29 0

= 290

(i) 8 ones × 5 = 40 = 4 tens + 0 ones

(ii) 5 tens × 5 = 25 tens

(iii) 25 tens + 4 tens = 29 tens

Hence 58 × 5 = 290

10.Multiply 37 by 8

Solution:

3 7

× 8th

5 6

+ 2 4 0

2 9 6

(i) 7 ones × 8 = 56 ones = 5 tens 6 ones

56 is placed so that 5 comes under tens and 6 comes under ones

(ii) 3 tens × 8 = 24 tens = 240 ones

= 2 hundreds, 4 tens and 0 ones

240 is placed under 56, so 2 comes under hundreds, 4 under tens, and 0 under ones.

Hence 37 × 8 = 296

2nd grade math practice

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