The process of adding units of length is exactly similar to adding ordinary numbers.

Learn how the length values ​​are arranged in different columns for adding length.

1. Add 15 m 18 cm and 16 m 22 cm

Solution:

Case 1:

Lengths to be added are converted into cm.

15 m 18 cm = 1500 cm + 18 cm = 1518 cm

16 m 22 cm = 1600 cm + 22 cm = 1622 cm

Well, sum

1 1
1518 cm

+ 1622 cm
3140 cm

= 31 m 40 cm²

Therefore 15 m 18 cm + 16 m 22 cm = 31 m 40 cm

Case 2:

m cm
1 1
15 18

+ 16 22
31 40

(i) The first cm are added, 18 cm + 22 cm = 40 cm. This sum is added to the cm column

(ii) Now meters are added, 15m + 16m = 31m. These 31m are placed under the m-column.

So total = 31 m 40 cm.

2. Add 16m 17cm and 20m 23cm

Solution:

Case 1:

Lengths to be added are converted into cm.

16 m 17 cm = 1600 cm + 17 cm = 1617 cm

20 m 23 cm = 2000 cm + 23 cm = 2023 cm

Well, sum

1
1617 cm

+ 2023 cm
3640 cm

= 36 m 40 cm

Therefore 16 m 17 cm + 20 m 23 cm = 36 m 40 cm

Case 2:

m cm
1
16 17
+ 20 23
36 40

(i) The first cm are added, 17 cm + 23 cm = 40 cm. This sum is added to the cm column

(ii) Now meters are added, 16m + 20m = 36m. These 36m are placed under the m-column.

So total = 36 m 40 cm.

3. Add 62m 34cm, 27m 73cm and 9m 5cm.

Solution:

 Let’s add Step I: Arrange the numbers vertically. Step II: Write the lengths to be added in m and cm as shown. Step III: First add inches from the right, then add the meters. So 62 m 34 cm + 27 m 73 cm + 9 m 5 cm = 99 m 12 cm

4th Add 45 m 37 cm and 31 m 92 cm.

Solution:

Case 1:

45 m 37 cm = (45 × 100) cm + 37 cm = (4500 + 37) cm = 4537 cm

31 m 92 cm = (31 × 100) cm + 92 cm = (3100 + 92) cm = 3192 cm

Well, sum

1
4537 cm

+ 3192 cm
7729 cm

= 77 m 29 cm²

So 45 m 37 cm + 31 m 92 cm = 77 m 29 cm

Case 2:

m cm
1
45 37

+ 31 92
77 29

(i) 37 cm + 92 cm = 129 cm = 1 m 29 cm. 29 is placed under the cm column and 1 m is transferred to the m column.

(ii) Now 1m + 45m + 31m = 77m. It is placed under the column m.

So total = 77 m 29 cm.

5. Add 38 m 26 cm, 7 m 5 cm and 45 m 73 cm.

Solution:

The length values ​​are arranged in columns of m and cm and then added.

m cm
21 1
38 26

7 05

+ 45 73
91 04

(i) 26 cm + 05 cm + 73 cm = 104 cm = 1 m 04 cm.

04 is placed under the cm column and 1 m is transferred.

(ii) 1 m + 38 m + 7 m + 45 m = 91 m and is placed under the m-pillar.

This gives the total = 91 m 04 cm

6th Add 4 km 476 m and 5 km 54 m.

Solution:

Case 1:

Kilometers are converted into meters

4 km 476 m = (4 × 1000) m + 476 m = 4000 m + 476 m = 4476 m

5 km 54 m = (5 × 1000) m + 54 m = 5000 m + 54 m = 5054 m

1 1
4476 m

+

5054 m
9530 m

= 9 km 530 m²

Because of this, 4 km 476 m + 5 km 54 m = 9 km 530 m

Case 2:

km m
1 1
4,476

+ 5 054
9 530

(i) 476 m + 054 m = 530 m, which goes below m.

(ii) 4 km + 5 km = 9 km, which is less than km.

Therefore the sum = 9 km 530 m

7th Add 37 km 963 m, 28 km 54 m and 8 km 181 m.

Solution:

Kilometers and meters are arranged in different columns and then added up.

km m
2 1 1
37 963

28 054

+ 8 181
74 198

(i) 963 m + 54 m + 181 m = 1198 m = 1 km 198 m.

198 m are placed under the meter column and 1 km is transferred.

(ii) 1 km + 37 km + 28 km + 8 km = 74 km

It is placed under the km column.

This gives the total = 74 km 198 m

m dm cm

26 7 8

+ 52 5 6

Solution:

m dm cm
1 1
26 7
8th

+ 5256th
793rd4th

(i) 8 cm + 6 cm = 14 cm = 1 dm 4 cm

4 cm is placed under the cm column and 1 dm is transferred.

(ii) 7 dm + 5 dm + 1 dm = 13 dm = 1 m 3 dm

3 dm is placed under the dm column and 1 m is transferred.

(iii) 1 m + 26 m + 52 m = 79 m

This gives the total = 79 m 3 dm 4 cm

● Related concepts

Standard length unit

Conversion of the standard length unit

Subtract the length