The process of adding units of length is exactly similar to adding ordinary numbers.
Learn how the length values are arranged in different columns for adding length.
1. Add 15 m 18 cm and 16 m 22 cm
Solution:
Case 1:
Lengths to be added are converted into cm.
15 m 18 cm = 1500 cm + 18 cm = 1518 cm
16 m 22 cm = 1600 cm + 22 cm = 1622 cm
Well, sum
1 1
1518 cm
+ 1622 cm
3140 cm
= 31 m 40 cm²
Therefore 15 m 18 cm + 16 m 22 cm = 31 m 40 cm
Case 2:
m cm
1 1
15 18
+ 16 22
31 40
(i) The first cm are added, 18 cm + 22 cm = 40 cm. This sum is added to the cm column
(ii) Now meters are added, 15m + 16m = 31m. These 31m are placed under the m-column.
So total = 31 m 40 cm.
2. Add 16m 17cm and 20m 23cm
Solution:
Case 1:
Lengths to be added are converted into cm.
16 m 17 cm = 1600 cm + 17 cm = 1617 cm
20 m 23 cm = 2000 cm + 23 cm = 2023 cm
Well, sum
1
1617 cm
+ 2023 cm
3640 cm
= 36 m 40 cm
Therefore 16 m 17 cm + 20 m 23 cm = 36 m 40 cm
Case 2:
m cm
1
16 17
+ 20 23
36 40
(i) The first cm are added, 17 cm + 23 cm = 40 cm. This sum is added to the cm column
(ii) Now meters are added, 16m + 20m = 36m. These 36m are placed under the m-column.
So total = 36 m 40 cm.
3. Add 62m 34cm, 27m 73cm and 9m 5cm.
Solution:
Let’s add Step I: Arrange the numbers vertically. Step II: Write the lengths to be added in m and cm as shown. Step III: First add inches from the right, then add the meters. |
So 62 m 34 cm + 27 m 73 cm + 9 m 5 cm = 99 m 12 cm
4th Add 45 m 37 cm and 31 m 92 cm.
Solution:
Case 1:
45 m 37 cm = (45 × 100) cm + 37 cm = (4500 + 37) cm = 4537 cm
31 m 92 cm = (31 × 100) cm + 92 cm = (3100 + 92) cm = 3192 cm
Well, sum
1
4537 cm
+ 3192 cm
7729 cm
= 77 m 29 cm²
So 45 m 37 cm + 31 m 92 cm = 77 m 29 cm
Case 2:
m cm
1
45 37
+ 31 92
77 29
(i) 37 cm + 92 cm = 129 cm = 1 m 29 cm. 29 is placed under the cm column and 1 m is transferred to the m column.
(ii) Now 1m + 45m + 31m = 77m. It is placed under the column m.
So total = 77 m 29 cm.
5. Add 38 m 26 cm, 7 m 5 cm and 45 m 73 cm.
Solution:
The length values are arranged in columns of m and cm and then added.
m cm
21 1
38 26
7 05
+ 45 73
91 04
(i) 26 cm + 05 cm + 73 cm = 104 cm = 1 m 04 cm.
04 is placed under the cm column and 1 m is transferred.
(ii) 1 m + 38 m + 7 m + 45 m = 91 m and is placed under the m-pillar.
This gives the total = 91 m 04 cm
6th Add 4 km 476 m and 5 km 54 m.
Solution:
Case 1:
Kilometers are converted into meters
4 km 476 m = (4 × 1000) m + 476 m = 4000 m + 476 m = 4476 m
5 km 54 m = (5 × 1000) m + 54 m = 5000 m + 54 m = 5054 m
Now add up
1 1
4476 m
+
5054 m
9530 m
= 9 km 530 m²
Because of this, 4 km 476 m + 5 km 54 m = 9 km 530 m
Case 2:
km m
1 1
4,476
+ 5 054
9 530
(i) 476 m + 054 m = 530 m, which goes below m.
(ii) 4 km + 5 km = 9 km, which is less than km.
Therefore the sum = 9 km 530 m
7th Add 37 km 963 m, 28 km 54 m and 8 km 181 m.
Solution:
Kilometers and meters are arranged in different columns and then added up.
km m
2 1 1
37 963
28 054
+ 8 181
74 198
(i) 963 m + 54 m + 181 m = 1198 m = 1 km 198 m.
198 m are placed under the meter column and 1 km is transferred.
(ii) 1 km + 37 km + 28 km + 8 km = 74 km
It is placed under the km column.
This gives the total = 74 km 198 m
8th. Add the following:
m dm cm
26 7 8
+ 52 5 6
Solution:
m dm cm
1 1
26 7 8th
+ 5256th
793rd4th
(i) 8 cm + 6 cm = 14 cm = 1 dm 4 cm
4 cm is placed under the cm column and 1 dm is transferred.
(ii) 7 dm + 5 dm + 1 dm = 13 dm = 1 m 3 dm
3 dm is placed under the dm column and 1 m is transferred.
(iii) 1 m + 26 m + 52 m = 79 m
This gives the total = 79 m 3 dm 4 cm
● Related concepts
● Standard length unit
● Conversion of the standard length unit
● Subtract the length
Math worksheets for 3rd grade
3rd grade math class
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